What is Nostr?
Jeremy [ARCHIVE] /
npub1q86…qwta
2023-06-07 18:26:57
in reply to nevent1q…t67c

Jeremy [ARCHIVE] on Nostr: πŸ“… Original date posted:2020-09-19 πŸ“ Original message:Antoine, Yes I think ...

πŸ“… Original date posted:2020-09-19
πŸ“ Original message:Antoine,

Yes I think you're a bit confused on where the actual sponsor vector is. If
you have a transaction chain A->B->C and a sponsor S_A, S_A commits to txid
A and A is unaware of S.


W.r.t your other points, I fully agree that the 1-to-N sponsored case is
very compelling. The consensus rules are clear that sponsor commitments are
non-rival, so there's no issue with allowing as many sponsors as possible
and including them in aggregate. E.g., if S_A and S'_A both sponsor A with
feerate(S*) > feerate(A), there's no reason not to include all of them in a
block. The only issue is denial of service in the mempool. In the future,
it would definitely be desirable to figure out rules that allow mempools to
track both multiple sponsors and multiple sponsor targets. But in the
interest of KISS, the current policy rules are designed to be minimally
invasive and maximally functional.

In terms of location for the sponsor vector, I'm relatively indifferent.
The annex is a possible location, but it's a bit odd as we really only need
to allow one such vector per tx, not one per input, and one per input would
enable some new use cases (maybe good, maybe bad). Further, being in the
witness space would mean that if two parties create a 2 input transaction
with a desired sponsor vector they would both need to specify it as you
can't sign another input's witness data. I wholeheartedly agree with the
sentiment though; there could be a more efficient place to put this data,
but nothing jumps out to me as both efficient and simple in implementation
(a new tx-level field sounds like a lot of complexity).


> n >=1 ? I think you can have at least one vector and this is matching the
code

yes, this has been fixed in the gist (cred to Dmitry Petukhov for pointing
it out first), but is correct in the code. Thank you for your careful
reading.
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