John Carlos Baez on Nostr: npub1ky223…rghvc - were you trying to reply to me? Your post isn't linked to ...

npub1ky223zcc4q69d8t0me4vg5uw8mw0yxeukjgvz6h92laqnenr0ajs5rghvc (npub1ky2…ghvc) - were you trying to reply to me? Your post isn't linked to anything.

For Schrodinger's equation, position eigenstates form a basis. Each of these eigenstates breaks translation invariance. How could Schrodinger's equation ever be translation-invariant? 🤔

It's not so hard.