Adam Back / @adam3us on Nostr: **R to @adam3us: you can solve that if you know the discrete log of A or B. if you ...
**R to @adam3us: you can solve that if you know the discrete log of A or B. if you know discrete log of A, you pick random c2 and r2, find out what c1 is and solve. like c=H(k*G,r1*G+c2*B), then c1=c-c2, and k=r1+c1*x, so r1=k-c1*x QED**
you can solve that if you know the discrete log of A or B. if you know discrete log of A, you pick random c2 and r2, find out what c1 is and solve. like c=H(k*G,r1*G+c2*B), then c1=c-c2, and k=r1+c1*x, so r1=k-c1*x QED**R to @adam3us: you can solve that if you know the discrete log of A or B. if you know discrete log of A, you pick random c2 and r2, find out what c1 is and solve. like c=H(k*G,r1*G+c2*B), then c1=c-c2, and k=r1+c1*x, so r1=k-c1*x QED**
you can so…
https://nitter.net/adam3us/status/1605984495810789391#m
you can solve that if you know the discrete log of A or B. if you know discrete log of A, you pick random c2 and r2, find out what c1 is and solve. like c=H(k*G,r1*G+c2*B), then c1=c-c2, and k=r1+c1*x, so r1=k-c1*x QED**R to @adam3us: you can solve that if you know the discrete log of A or B. if you know discrete log of A, you pick random c2 and r2, find out what c1 is and solve. like c=H(k*G,r1*G+c2*B), then c1=c-c2, and k=r1+c1*x, so r1=k-c1*x QED**
you can so…
https://nitter.net/adam3us/status/1605984495810789391#m