Colin the Mathmo on Nostr: Here's a challenge for my mathsy people here on Mathstodon ... In the numbers game on ...
Here's a challenge for my mathsy people here on Mathstodon ...
In the numbers game on Countdown one is given a target to reach using six numbers and the standard four operations.
So:
339 = ((50 + 4) × (3 − 1) + 5) × 3
It is stipulated in the rules that intermediate results must be positive integers, so this is not allowed:
339 = 50 × (4/5 + 3 + 3) – 1
Can you find a target and six numbers such that it cannot be reached by following the rules, but it *can* be reached with non-integer intermediate values?
I don't know, but I've not tried especially hard. I thought it might be a thing people here might like a go at.
Have at it !!
(Boosts welcome, if you're comfortable doing so).
In the numbers game on Countdown one is given a target to reach using six numbers and the standard four operations.
So:
339 = ((50 + 4) × (3 − 1) + 5) × 3
It is stipulated in the rules that intermediate results must be positive integers, so this is not allowed:
339 = 50 × (4/5 + 3 + 3) – 1
Can you find a target and six numbers such that it cannot be reached by following the rules, but it *can* be reached with non-integer intermediate values?
I don't know, but I've not tried especially hard. I thought it might be a thing people here might like a go at.
Have at it !!
(Boosts welcome, if you're comfortable doing so).