Ben Wehrman on Nostr: Lil quick test using some PNW landmarks I'm familiar with... (See reference chart of ...

Lil quick test using some PNW landmarks I'm familiar with...

(See reference chart of how much drop in elevation we should see due to earth's curvature over certain ground distances.)

Here's a photo of Mt. Rainier from Vancouver B.C. Almost exactly 200 miles distance, which equal 5.05 miles of drop from curvature.

Tippy top of Mt. Rainier is 2.72 miles in height, so on net, from Vancouver B.C., that peak of the summit should be well hidden 2.33 MILES below ground level from the perspective of the photographer.

Yet you can see the BASE of the mountain, essentially bone-flat with Vancouver despite 200 miles of distance. That's mathematically impossible based on the globe model. #FlatEarth

quoting nevent1q…x3s4

If you live somewhere where you can see a city, landmass, or landmark VERY far away (10 miles plus, ideally), then you can easily test the heliocentric globe model for yourself. (Binoculars/telescope are encouraged if you have them, so you can see even further; all that matters is that you can establish a visual.)

Once you've made eye contact with Location B from Location A (your location), refer to this chart for the corresponding distance of drop there should be from the curvature of the Earth, according to the official globe measurements.

Do you see the amount of drop that you should?

Report back with your findings!