myrmepropagandist on Nostr: The AC method needs to be "developed" and the road to the AC method is all about ...

The AC method needs to be "developed" and the road to the AC method is all about factoring by grouping.

x²+4x-60=0

This quadratic isn't so bad. a=1 so you just need to think of numbers that multiply to -60 but also add to +4

But what if a!=1?

6x²-13x-5=0

Now we have a problem. The way I'd solve this would be to start guessing:

(?x ?)(?x ?)

But I can see why some people find this unreasonable. Is it:

(2x ?)(3x ?) or (6x ?)(x ?)

The possibilities just expanded.

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