Aaron Toponce ⚛️:debian: on Nostr: I will show that 3=0. Let x²+x+1=0. Clearly, x=1 is not a solution to the equation. ...
I will show that 3=0.
Let x²+x+1=0. Clearly, x=1 is not a solution to the equation. Divide both sides by "x":
x+1+1/x=0 => x+1=-1/x
Thus, x²+x+1=0 => x²-1/x=0. Multiply by "x":
x³-1=0. Clearly, x=1 is a solution to this equation. So going back to the original equation:
1²+1+1=0 => 3=0
QED
#math
Let x²+x+1=0. Clearly, x=1 is not a solution to the equation. Divide both sides by "x":
x+1+1/x=0 => x+1=-1/x
Thus, x²+x+1=0 => x²-1/x=0. Multiply by "x":
x³-1=0. Clearly, x=1 is a solution to this equation. So going back to the original equation:
1²+1+1=0 => 3=0
QED
#math