Tier Nolan [ARCHIVE] on Nostr: π Original date posted:2016-01-11 π Original message:On Fri, Jan 8, 2016 at ...
π
Original date posted:2016-01-11
π Original message:On Fri, Jan 8, 2016 at 3:46 PM, Gavin Andresen via bitcoin-dev <
bitcoin-dev at lists.linuxfoundation.org> wrote:
> How many years until we think a 2^84 attack where the work is an ECDSA
> private->public key derivation will take a reasonable amount of time?
>
I think the EC multiply is not actually required. With compressed public
keys, the script selection rule can just be a sha256 call instead.
V is the public key of the victim, and const_pub_key is the attacker's
public key.
if prev_hash % 2 == 0:
script = "2 V 0x02%s 2 CHECKMULTISIG" % (sha256(prev_hash)))
else:
script = "CHECKSIG %s OP_DROP" % (prev_hash, const_pub_key)
next_hash = ripemd160(sha256(script))
If a collision is found, there is a 50% chance that the two scripts have
different parity and there is a 50% chance that a compressed key is a valid
key.
This means that you need to run the algorithm 4 times instead of 2.
The advantage is that each step is 2 sha256 calls and a ripemd160 call. No
EC multiply is required.
-------------- next part --------------
An HTML attachment was scrubbed...
URL: <http://lists.linuxfoundation.org/pipermail/bitcoin-dev/attachments/20160111/be7bd486/attachment.html>
π Original message:On Fri, Jan 8, 2016 at 3:46 PM, Gavin Andresen via bitcoin-dev <
bitcoin-dev at lists.linuxfoundation.org> wrote:
> How many years until we think a 2^84 attack where the work is an ECDSA
> private->public key derivation will take a reasonable amount of time?
>
I think the EC multiply is not actually required. With compressed public
keys, the script selection rule can just be a sha256 call instead.
V is the public key of the victim, and const_pub_key is the attacker's
public key.
if prev_hash % 2 == 0:
script = "2 V 0x02%s 2 CHECKMULTISIG" % (sha256(prev_hash)))
else:
script = "CHECKSIG %s OP_DROP" % (prev_hash, const_pub_key)
next_hash = ripemd160(sha256(script))
If a collision is found, there is a 50% chance that the two scripts have
different parity and there is a 50% chance that a compressed key is a valid
key.
This means that you need to run the algorithm 4 times instead of 2.
The advantage is that each step is 2 sha256 calls and a ripemd160 call. No
EC multiply is required.
-------------- next part --------------
An HTML attachment was scrubbed...
URL: <http://lists.linuxfoundation.org/pipermail/bitcoin-dev/attachments/20160111/be7bd486/attachment.html>