Stephen Brooks 🦆 on Nostr: npub1qe0dd…zausg If a is x->1-x and b is x->1/x, both self-inverse, then this is ...

npub1qe0dds67kfrdvafyywzmq97z0j4s98qv5hygsrfg283l3ukqmm6spzausg (npub1qe0…ausg) If a is x->1-x and b is x->1/x, both self-inverse, then this is saying that bababa=e, or abab=ba, or aba=bab. That third one is x/(x-1).